A convex lens has power P. It is cut into two | vedclass

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Question

(A) When a lens is cut along its principal axis,the power of each half remains the same as the original lens,i.e.,$P' = P$. However,if the lens is cut

Vedclass · Accepted Answer

Power of $L_{1} = \frac{P}{2}$

Vedclass · Answer

(A) When a lens is cut along its principal axis,the power of each half remains the same as the original lens,i.e.,$P' = P$. However,if the lens is cut perpendicular to the principal axis,the power of each piece becomes half of the original power,i.e.,$P'' = \frac{P}{2}$. In the given figure,the lens is first cut along the principal axis,resulting in two halves,each having power $P$. Then,one of these halves is cut perpendicular to the principal axis,resulting in two pieces $L_{2}$ and $L_{3}$,each having power $\frac{P}{2}$. The other half,$L_{1}$,remains unchanged and thus retains its power $P$. Therefore,the incorrect option is that the power of $L_{1}$ is $\frac{P}{2}$.

$A$ convex lens has power $P$. It is cut into two halves along its principal axis. Further,one piece (out of the two halves) is cut into two halves perpendicular to the principal axis (as shown in the figure). Choose the incorrect option for the reported pieces.

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