$A$ coordination compound $CrCl_{3} \cdot 4 H_{2} O$ precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.

(N/A) The compound gives a white precipitate of $AgCl$ when treated with $AgNO_{3}$,which indicates that at least one $Cl^{-}$ ion is present in the ionization sphere.
Since the molar conductance corresponds to a total of two ions,the complex must dissociate into two ions: one cation and one anion.
Therefore,the complex must be $[Cr(H_{2}O)_{4}Cl_{2}]Cl$,which dissociates as $[Cr(H_{2}O)_{4}Cl_{2}]Cl \rightarrow [Cr(H_{2}O)_{4}Cl_{2}]^{+} + Cl^{-}$.
The structural formula is $[Cr(H_{2}O)_{4}Cl_{2}]Cl$ and its $IUPAC$ name is Tetraaquadichloridochromium$(III)$ chloride.