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(D) Since the cow is tied at the corner of a rectangular field,the area it can graze forms a sector of a circle with a radius $r = 14\, m$ and a centr

Vedclass · Accepted Answer

$154$

Vedclass · Answer

(D) Since the cow is tied at the corner of a rectangular field,the area it can graze forms a sector of a circle with a radius $r = 14\, m$ and a central angle of $90^{\circ}$ (as the corner of a rectangle is $90^{\circ}$).The area of the sector is given by the formula: $	ext{Area} = \frac{	heta}{360^{\circ}} 	imes \pi r^2$.Substituting the values: $	ext{Area} = \frac{90^{\circ}}{360^{\circ}} 	imes \frac{22}{7} 	imes 14 	imes 14$.$	ext{Area} = \frac{1}{4} 	imes \frac{22}{7} 	imes 196$.$	ext{Area} = \frac{1}{4} 	imes 22 	imes 28$.$	ext{Area} = 154\, m^2$.

$A$ cow is tied by a rope at the corner of a rectangular field. If the length of the rope is $14\, m$,then the area of the field which the cow could graze is.......$m^2$

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