A current I flows along the length of an infi | vedclass

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(B) According to Ampere's circuital law,the line integral of the magnetic field $\vec{B}$ around any closed loop is equal to $\mu_0$ times the total c

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The magnetic field at any point inside the pipe is zero

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(B) According to Ampere's circuital law,the line integral of the magnetic field $\vec{B}$ around any closed loop is equal to $\mu_0$ times the total current $I_{	ext{enclosed}}$ passing through the surface bounded by the loop: $\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{	ext{enclosed}}$.For an infinitely long,thin-walled pipe carrying current $I$ along its length,any closed loop chosen inside the pipe encloses zero current $(I_{	ext{enclosed}} = 0)$.Therefore,$\oint \vec{B} \cdot d\vec{l} = 0$,which implies that the magnetic field $\vec{B}$ at any point inside the pipe is zero.

$A$ current $I$ flows along the length of an infinitely long,straight and thin-walled pipe. Then

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