$A$ current of $1\, A$ is drawn by a filament of an electric bulb. The number of electrons passing through a cross-section of the filament in $16$ seconds would be roughly:

  • A
    $10^{23}$
  • B
    $10^{16}$
  • C
    $10^{18}$
  • D
    $10^{20}$

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