A cylindrical tower is 5 , m in diameter and | vedclass

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(D) The diameter of the cylinder is $d = 5 \, m$,so the radius is $r = \frac{d}{2} = 2.5 \, m$.The height of the cylinder is $h = 14 \, m$.The curved

Vedclass · Accepted Answer

$110$

Vedclass · Answer

(D) The diameter of the cylinder is $d = 5 \, m$,so the radius is $r = \frac{d}{2} = 2.5 \, m$.The height of the cylinder is $h = 14 \, m$.The curved surface area of a cylinder is given by the formula $A = 2 \pi r h$.Substituting the values: $A = 2 	imes \frac{22}{7} 	imes 2.5 	imes 14$.$A = 2 	imes 22 	imes 2.5 	imes 2 = 220 \, m^{2}$.The cost of white washing is $50$ paise per $m^{2}$,which is equal to $₹ 0.50$ per $m^{2}$.Total cost $= 220 	imes 0.50 = ₹ 110$.

$A$ cylindrical tower is $5 \, m$ in diameter and $14 \, m$ high. The cost of white washing its curved surface at $50$ paise per $m^{2}$ is (in $Rs.$)

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