$A$ cylindrical vessel of $90 \ cm$ height is kept filled up to the brim. It has four holes $1, 2, 3, 4$ which are respectively at heights of $20 \ cm, 30 \ cm, 45 \ cm,$ and $50 \ cm$ from the horizontal floor $PQ.$ The water falling at the maximum horizontal distance from the vessel comes from:

$A$ cylindrical vessel of $40 \text{ cm}$ radius is completely filled with water and its capacity is $528 \text{ dm}^3$. The vessel is placed on a solid block of exactly the same height as the vessel. If a small hole is made at $70 \text{ cm}$ below the top of the water level, then the horizontal range of water falling on the ground in the beginning is . . . . . . $\text{cm}$.

Water flows out of a hole on the side of a bucket and follows a parabolic path. If the bucket falls freely under gravity, ignoring air resistance, the water flow

$A$ large vessel completely filled with water has two holes '$A$' and '$B$' at depths '$h$' and '$4h$' from the top. Hole '$A$' is a square of side '$L$' and hole '$B$' is a circle of radius '$R$'. If the same quantity of water is flowing per second from both holes,then the side of the square hole is:

$A$ cylindrical tank has a hole of $1 \ cm^2$ in its bottom. If the water is allowed to flow into the tank from a tube above it at the rate of $70 \ cm^3/s$,then the maximum height up to which water can rise in the tank is: $(g = 9.8 \ m/s^2)$ (in $cm$)

In a cylindrical water tank,there are two small holes $A$ and $B$ on the wall. Hole $A$ is at a depth of $h_1$ from the water surface,and hole $B$ is at a height of $h_2$ from the bottom of the tank. The total height of the water surface from the bottom of the tank is $H$. Water coming out from both holes strikes the ground at the same point $S$. Find the ratio of $h_1$ and $h_2$.