$A$ fair coin is tossed $100$ times. The probability of getting tails an odd number of times is

In a binomial distribution,if $n=4$ and $P(X=0)=\frac{16}{81}$,then $P(X=4)=$

$A$ random variable $X$ has a probability mass function $P(X=x) = \frac{{}^4C_x}{2^4}$ for $x = 0, 1, 2, 3, 4$. If $\mu$ and $\sigma^2$ are the mean and variance of the random variable $X$ respectively,then:

Out of $100$ people selected at random,$10$ have a common cold. If five persons are selected at random from the group,then the probability that at most one person will have a common cold is

In a Binomial distribution $B(n, p)$,the sum and product of the mean and the variance are $5$ and $6$ respectively,then $6(n+p-q)=$

The probability that $A$ wakes up before the alarm rings is $0.4$. Then,the mean and variance of the number of times $A$ wakes up before the alarm rings,in the next $7$ days respectively are: