$A$ farmer has a field in the form of a parallelogram $PQRS$. She took any point $A$ on $RS$ and joined it to points $P$ and $Q$. In how many parts is the field divided? What are the shapes of these parts? The farmer wants to sow wheat and pulses in equal portions of the field separately. How should she do it?

(N/A) The farmer has a field in the form of a parallelogram $PQRS$,and a point $A$ is situated on $RS$.
Let us join $AP$ and $AQ$.
Obviously,the field is divided into three parts,i.e.,$\Delta APS$,$\Delta PAQ$,and $\Delta QAR$. These parts are triangular in shape.
Since $\Delta PAQ$ and parallelogram $PQRS$ are on the same base $PQ$ and between the same parallels $PQ$ and $RS$:
$\therefore \text{ar}(\Delta PAQ) = \frac{1}{2} \text{ar}(\text{parallelogram } PQRS) \dots(1)$
$\Rightarrow \text{ar}(\text{parallelogram } PQRS) - \text{ar}(\Delta PAQ) = \text{ar}(\text{parallelogram } PQRS) - \frac{1}{2} \text{ar}(\text{parallelogram } PQRS)$
$\Rightarrow [\text{ar}(\Delta APS) + \text{ar}(\text{QAR})] = \frac{1}{2} \text{ar}(\text{parallelogram } PQRS) \dots(2)$
From $(1)$ and $(2)$,we have:
$\text{ar}(\Delta PAQ) = \text{ar}(\Delta APS) + \text{ar}(\Delta QAR)$
Thus,the farmer can sow wheat in $\Delta PAQ$ and pulses in the combined area of $\Delta APS$ and $\Delta QAR$,or vice versa.