(B) Let $BC = 18 \, m$ be the flag pole and its shadow be $AB = 9.6 \, m$. The distance of the top of the pole $(C)$ from the far end of the shadow $(

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(B) Let $BC = 18 \, m$ be the flag pole and its shadow be $AB = 9.6 \, m$. The distance of the top of the pole $(C)$ from the far end of the shadow $(A)$ is $AC$.In right-angled $\triangle ABC$,by Pythagoras theorem:$AC^2 = AB^2 + BC^2$$AC^2 = (9.6)^2 + (18)^2$$AC^2 = 92.16 + 324$$AC^2 = 416.16$$AC = \sqrt{416.16} = 20.4 \, m$Hence,the required distance is $20.4 \, m$.

Class 10 Mathematics Triangles Mix Examples - Triangles

Medium

$A$ flag pole $18 \, m$ high casts a shadow $9.6 \, m$ long. Find the distance of the top of the pole from the far end of the shadow. (in $m$)

A
$10.4$
B
$20.4$
C
$20.6$
D
$30.4$

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$A$ flag pole $18 \, m$ high casts a shadow $9.6 \, m$ long. Find the distance of the top of the pole from the far end of the shadow. (in $m$)

Similar Questions

In the figure,if $\triangle ABC \sim \triangle DEF$ and their side lengths (in $cm$) are as marked,find the lengths of the sides of each triangle.

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $\overline{BM}$ is an altitude to the hypotenuse $\overline{AC}$. If $BM = 12$ and $CM = 18$,find $AB$.

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