$A$ fluid container containing a liquid of density $\rho$ is accelerating upward with acceleration $a$ along an inclined plane of inclination $\alpha$ as shown. Then the angle of inclination $\theta$ of the free surface is:

  • A
    $\tan^{-1}\left[\frac{a}{g\cos\alpha}\right]$
  • B
    $\tan^{-1}\left[\frac{a+g\sin\alpha}{g\cos\alpha}\right]$
  • C
    $\tan^{-1}\left[\frac{a-g\sin\alpha}{g(1+\cos\alpha)}\right]$
  • D
    $\tan^{-1}\left[\frac{a-g\sin\alpha}{g(1-\cos\alpha)}\right]$

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