$A$ force $\overrightarrow{F} = 5\hat{i} + 6\hat{j} + 4\hat{k}$ acting on a body produces a displacement $\overrightarrow{S} = 6\hat{i} - 5\hat{k}$. The work done by the force is: (in $J$)

$A$ body of mass $m$ starts from rest and acquires a velocity $v$ in time $t_1$. The work done in time $t$ is proportional to:

Work done

Force acting on a particle moving in a straight line varies with the velocity of the particle as $F = \frac{K}{v}$,where $K$ is a constant. The work done by this force in time $t$ is

$A$ chain of mass $m$ and length $\ell$ is held on a frictionless table in such a way that its $\frac{2 \ell}{5}$ part is hanging below the edge of the table. Find the work done to pull the hanging part of the chain up onto the table.

The figure shows a mass $m$ on a frictionless surface. It is connected to a rigid wall by means of a massless spring of spring constant $k$. Initially,the spring is at its natural position. If a force of constant magnitude $F$ starts acting on the block towards the right,then the speed of the block when the deformation in the spring is $x$ will be