A force overrightarrow{F} = 2i + j - k acts a | vedclass

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(C) The position vector of point $A$ is $\overrightarrow{r} = 2i - j + 0k$.The force vector is $\overrightarrow{F} = 2i + j - k$.The moment of force $

Vedclass · Accepted Answer

$i + 2j + 4k$

Vedclass · Answer

(C) The position vector of point $A$ is $\overrightarrow{r} = 2i - j + 0k$.The force vector is $\overrightarrow{F} = 2i + j - k$.The moment of force $\overrightarrow{M}$ about the origin is given by the cross product $\overrightarrow{r} 	imes \overrightarrow{F}$.$\overrightarrow{M} = \begin{vmatrix} i & j & k \ 2 & -1 & 0 \ 2 & 1 & -1 \end{vmatrix}$$= i((-1)(-1) - (0)(1)) - j((2)(-1) - (0)(2)) + k((2)(1) - (-1)(2))$$= i(1 - 0) - j(-2 - 0) + k(2 + 2)$$= i + 2j + 4k$.

$A$ force $\overrightarrow{F} = 2i + j - k$ acts at a point $A$,whose position vector is $2i - j$. The moment of $\overrightarrow{F}$ about the origin is:

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