$A$ tuning fork of frequency $256\, Hz$ resonates with a closed organ pipe of length $25.4\, cm$. If the length of the pipe is increased by $2\, mm$,the number of beats per second will be:

$A$ source of sound placed at the open end of a resonance column sends an acoustic wave of pressure amplitude ${\rho _0}$ inside the tube. If the atmospheric pressure is ${\rho _A},$ then the ratio of maximum and minimum pressure at the closed end of the tube will be

The two nearest harmonics of a tube closed at one end and open at the other end are $220\, Hz$ and $260\, Hz$. What is the fundamental frequency of the system in $Hz$?

Two closed organ pipes of length $100 \,cm$ and $101 \,cm$ produce $16$ beats in $20 \,s$. When each pipe is sounded in its fundamental mode,calculate the velocity of sound in $m/s$.

In the fundamental mode, the time required for a sound wave to reach the closed end of a pipe filled with air is $t$ seconds. What is the frequency of vibration of the air column? ($\lambda$ = wavelength of the wave)

$A$ pipe open at both ends has a fundamental frequency $f$ in air. The pipe is dipped vertically in water so that half of its length is in water. The fundamental frequency of the air column is now ..... $f$.