A frictionless heat engine can be 100 % effic | vedclass

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(C) The efficiency $\eta$ of a Carnot heat engine is given by the formula $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the source (input) temperature a

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$0 \, K$

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(C) The efficiency $\eta$ of a Carnot heat engine is given by the formula $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ is the source (input) temperature and $T_2$ is the sink (exhaust) temperature in Kelvin.For the engine to be $100 \%$ efficient,$\eta$ must be equal to $1$.Substituting $\eta = 1$ into the equation: $1 = 1 - \frac{T_2}{T_1}$.This implies $\frac{T_2}{T_1} = 0$,which means $T_2 = 0 \, K$.Therefore,a heat engine can be $100 \%$ efficient only if its exhaust temperature is absolute zero $(0 \, K)$.

$A$ frictionless heat engine can be $100 \%$ efficient only if its exhaust temperature is ............

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