$A$ gas for which $\gamma = 1.5$ is suddenly compressed to $\frac{1}{4}$ of its initial volume. What is the ratio of the final pressure to the initial pressure?

$5.6 \ L$ of helium gas at $STP$ is adiabatically compressed to $0.7 \ L$. If the initial temperature of the gas is $T \ K$,the work done in the process is ($R$ is the universal gas constant in $SI$ units).

What is an adiabatic process? Derive an expression for work done in an adiabatic process.

$A$ gas at $N.T.P.$ is suddenly compressed to one-fourth of its original volume. If $\gamma = 1.5$,then the final pressure is

$A$ gas at $NTP$ is suddenly compressed to one-fourth of its original volume. If $\gamma$ is supposed to be $\frac{3}{2}$,then the final pressure is........ atmosphere.

Slope of isotherm for a gas (having $\gamma = 5/3$) is $3 \times 10^5 \, N/m^2$. If the same gas is undergoing adiabatic change,then the adiabatic elasticity at that instant is ........... $\times 10^5 \, N/m^2$.