A general wishing to draw up his 16160 men in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the number of men in the front row be $x$. Since the men are arranged in a solid square, the total number of men used in the square is $x^2$.G

Vedclass · Accepted Answer

$127$

Vedclass · Answer

(A) Let the number of men in the front row be $x$. Since the men are arranged in a solid square, the total number of men used in the square is $x^2$.Given that there are $16160$ men in total and $31$ men are left over, the number of men used in the square is $16160 - 31 = 16129$.Therefore, $x^2 = 16129$.To find $x$, we calculate the square root of $16129$: $x = \sqrt{16129} = 127$.Thus, the number of men in the front row is $127$.

$A$ general wishing to draw up his $16160$ men in the form of a solid square found that he had $31$ men over. The number of men in the front row is:

Similar Questions

$\sqrt{11449} \times \sqrt{6241} - (54)^{2} = \sqrt{?} + (74)^{2}$

Given that $\sqrt{4096} = 64$,the value of $\sqrt{4096} + \sqrt{40.96} + \sqrt{0.004096}$ is

$\left(\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}+\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)$ simplifies to

The value of $\frac{\sqrt{80}-\sqrt{112}}{\sqrt{45}-\sqrt{63}}$ is

Find the least number,which,when multiplied with $74088$ will make it a perfect square.

Vedclass Test Series

Exam Paper Generator

Online Exam Module