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(D) Given that the number of atoms per unit cell,$z = 4$,the crystal structure is face-centered cubic $(fcc)$.For an $fcc$ unit cell,the relationship

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$127$

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(D) Given that the number of atoms per unit cell,$z = 4$,the crystal structure is face-centered cubic $(fcc)$.For an $fcc$ unit cell,the relationship between the edge length $(a)$ and the atomic radius $(r)$ is given by $a = 2\sqrt{2}r$.Therefore,$r = \frac{a}{2\sqrt{2}}$.Substituting the given values: $r = \frac{361 \, pm}{2 	imes 1.414} = \frac{361}{2.828} \approx 127.65 \, pm$.Rounding to the nearest integer,the radius is $127 \, pm$.

$A$ given metal crystallises out with a cubic structure having edge length of $361 \, pm$. If there are four metal atoms in one unit cell,what is the radius of one atom? .............. $pm$

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