A glass lens is placed in a medium in which i | vedclass

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Question

(C) According to the Lens Maker's Formula,the focal length $f_l$ of a lens in a medium is given by $\frac{1}{f_l} = (_{\mu} - 1) \left( \frac{1}{R_1}

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Equal to the refractive index of glass

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(C) According to the Lens Maker's Formula,the focal length $f_l$ of a lens in a medium is given by $\frac{1}{f_l} = (_{\mu} - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$,where $_{\mu}$ is the refractive index of the lens material with respect to the medium.If the lens behaves like a glass plate,its focal length $f_l$ must be infinite $(\infty)$,meaning the lens has no converging or diverging power.For $f_l = \infty$,the term $(_{\mu} - 1)$ must be zero.This implies $_{\mu} = 1$.Since $_{\mu} = \frac{\mu_g}{\mu_m}$ (where $\mu_g$ is the refractive index of glass and $\mu_m$ is the refractive index of the medium),we have $\frac{\mu_g}{\mu_m} = 1$,which means $\mu_g = \mu_m$.Therefore,the refractive index of the medium must be equal to the refractive index of the glass.

$A$ glass lens is placed in a medium in which it is found to behave like a glass plate. The refractive index of the medium will be:

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