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(B) Given: Diameter of the cone $d = 42 \, m$,so radius $r = 21 \, m$. Height $h = 20 \, m$.First,calculate the slant height $l$ of the cone using the

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$₹ 143550$

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(B) Given: Diameter of the cone $d = 42 \, m$,so radius $r = 21 \, m$. Height $h = 20 \, m$.First,calculate the slant height $l$ of the cone using the formula $l = \sqrt{r^2 + h^2}$.$l = \sqrt{21^2 + 20^2} = \sqrt{441 + 400} = \sqrt{841} = 29 \, m$.The area of the canvas required is the curved surface area of the cone,given by $CSA = \pi r l$.$CSA = \frac{22}{7} 	imes 21 	imes 29 = 22 	imes 3 	imes 29 = 1914 \, m^2$.The cost of the canvas is $1914 \, m^2 	imes ₹ 75/m^2 = ₹ 143550$.

$A$ heap of wheat is in the form of a cone whose diameter is $42 \, m$ and height is $20 \, m$. The heap is to be covered by canvas to protect it from rain. If the price of canvas is $₹ 75$ per $m^2$,find the cost of the canvas required.

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