A well with 14, m inside diameter is dug 50, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The volume of the earth taken out from the well is equal to the volume of the cylinder: $V = \pi r^2 h$.$2$. Given diameter $d = 14\, m$,so r

Vedclass · Accepted Answer

$70$

Vedclass · Answer

(D) $1$. The volume of the earth taken out from the well is equal to the volume of the cylinder: $V = \pi r^2 h$.$2$. Given diameter $d = 14\, m$,so radius $r = 7\, m$. Depth $h = 50\, m$.$3$. $V = \frac{22}{7} 	imes 7 	imes 7 	imes 50 = 22 	imes 7 	imes 50 = 7700\, m^3$.$4$. This earth is spread over a rectangular field of area $A = 110\, m 	imes 100\, m = 11000\, m^2$.$5$. Let the increase in height be $H$. Then,$V = A 	imes H$.$6$. $7700 = 11000 	imes H$.$7$. $H = \frac{7700}{11000} = 0.7\, m$.$8$. Converting to $cm$: $0.7 	imes 100 = 70\, cm$.

$A$ well with $14\, m$ inside diameter is dug $50\, m$ deep. Earth taken out of it is spread all around a rectangular field of length $110\, m$ and width $100\, m$. Find the increase in the height of the field (in $cm$).

Similar Questions

$A$ sphere and a cylinder of the same radius have equal volumes. By what percentage does the diameter of the cylinder exceed its height?

Find the surface area of a sphere of radius $30 \, cm$ $(\pi = 3.14)$ (in $cm^2$).

The radii of two cylinders are in the ratio of $2:3$ and their heights are in the ratio of $5:3$. The ratio of their volumes is

$A$ conical tent with radius $7\, m$ and slant height $12\, m$ is to be made. How many metres of $2\, m$ wide tarpaulin will be required? If the price of tarpaulin is ₹ $48$ per meter,find the cost of the tarpaulin.

Curved surface area of a hemisphere $= \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module