A hundred turns of insulated copper wire are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total charge $Q$ that flows through the circuit is given by the formula $Q = \frac{\Delta \phi}{R}$,where $\Delta \phi$ is the change in magne

Vedclass · Accepted Answer

$2 	imes 10^{-2} \ C$

Vedclass · Answer

(A) The total charge $Q$ that flows through the circuit is given by the formula $Q = \frac{\Delta \phi}{R}$,where $\Delta \phi$ is the change in magnetic flux and $R$ is the total resistance.Given:Number of turns $N = 100$Area $A = 1 	imes 10^{-3} \ m^2$Resistance $R = 10 \ \Omega$Initial magnetic induction $B_i = 1 \ Wb/m^2$Final magnetic induction $B_f = -1 \ Wb/m^2$ (opposite direction)Change in magnetic induction $\Delta B = |B_f - B_i| = |(-1) - 1| = 2 \ Wb/m^2$.The change in flux is $\Delta \phi = N \cdot A \cdot \Delta B$.Substituting the values: $\Delta \phi = 100 	imes (1 	imes 10^{-3}) 	imes 2 = 0.2 \ Wb$.Now,calculating the charge: $Q = \frac{0.2}{10} = 0.02 \ C = 2 	imes 10^{-2} \ C$.

Similar Questions

The figure shows a conducting loop placed in a magnetic field. The magnetic flux through the loop changes according to the equation $\phi = 5t - 10t^2$. What is the direction and magnitude of the induced current at $t = 0.25\, s$?

$A$ magnetic field $B = 2t + 4t^{2}$ (where $t$ is time) is applied perpendicular to the plane of a circular wire of radius $r$ and resistance $R$. If all units are in $SI$, the electric charge that flows through the circular wire during $t = 0 \ s$ to $t = 2 \ s$ is:

Three resistances of magnitude $R$ each are connected in the form of an equilateral triangle of side $a$. The combination is placed in a magnetic field $B = B_0 e^{-\lambda t}$ perpendicular to its plane. The induced current in the circuit is given by:

$A$ magnetic field of $2 \times 10^{-2} \,T$ acts at right angles to a coil of area $100 \,cm^2$ with $50$ turns. The average e.m.f. induced in the coil is $0.1 \,V$, when it is removed from the field in time $t$. The value of $t$ is (in seconds): (in $s$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module