$A$ hydrated solid $X$ on heating initially gives a monohydrated compound $Y$. $Y$ upon heating above $373 \ K$ leads to an anhydrous white powder $Z$. $X$ and $Z$,respectively,are
- AWashing soda and soda ash.
- BWashing soda and dead burnt plaster.
- CBaking soda and dead burnt plaster.
- DBaking soda and soda ash.
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Similar Questions
The correct solubility order is/are:
$I. CaCO_3 > SrCO_3 > BaCO_3$
$II. Li_2CO_3 < Na_2CO_3 < K_2CO_3$
$III. K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$
$IV. Na_2CO_3 > K_2CO_3 > Rb_2CO_3$
$I. CaCO_3 > SrCO_3 > BaCO_3$
$II. Li_2CO_3 < Na_2CO_3 < K_2CO_3$
$III. K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$
$IV. Na_2CO_3 > K_2CO_3 > Rb_2CO_3$
Assertion : $Al(OH)_3$ is insoluble in $NH_4OH$ but soluble in $NaOH$.
Reason : $NaOH$ is a strong alkali.
Reason : $NaOH$ is a strong alkali.
MediumAIIMS 1997
View SolutionOn heating $ZnCl_2 \cdot 2H_2O$,the compound obtained is
Medium
View SolutionMatch the following compounds (Column-$I$) with their uses (Column-$II$):
Column-$I$ Column-$II$ $I. Ca(OH)_2$ $A$. Casts of statues $II. NaCl$ $B$. White wash $III. CaSO_4 \cdot \frac{1}{2}H_2O$ $C$. Antacid $IV. CaCO_3$ $D$. Washing soda preparation
| Column-$I$ | Column-$II$ |
|---|---|
| $I. Ca(OH)_2$ | $A$. Casts of statues |
| $II. NaCl$ | $B$. White wash |
| $III. CaSO_4 \cdot \frac{1}{2}H_2O$ | $C$. Antacid |
| $IV. CaCO_3$ | $D$. Washing soda preparation |
Tempered steel is
Easy
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