A jar contains 10 red marbles and 30 green on | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the number of red marbles to be added be $x$.Initially,the number of red marbles is $10$ and green marbles is $30$,so the total number of marb

Vedclass · Accepted Answer

$35$

Vedclass · Answer

(C) Let the number of red marbles to be added be $x$.Initially,the number of red marbles is $10$ and green marbles is $30$,so the total number of marbles is $10 + 30 = 40$.After adding $x$ red marbles,the new number of red marbles becomes $10 + x$ and the new total number of marbles becomes $40 + x$.According to the problem,the percentage of red marbles should be $60 \%$.Therefore,$\frac{10+x}{40+x} = \frac{60}{100}$.Simplifying the fraction,$\frac{10+x}{40+x} = \frac{3}{5}$.Cross-multiplying gives $5(10 + x) = 3(40 + x)$.$50 + 5x = 120 + 3x$.$5x - 3x = 120 - 50$.$2x = 70$.$x = 35$.Thus,$35$ red marbles must be added.

$A$ jar contains $10$ red marbles and $30$ green ones. How many red marbles must be added to the jar so that $60 \%$ of the marbles will be red?

Similar Questions

The price of an article was first increased by $10 \%$ and then again by $20 \%$. If the final increased price is $₹ 33$,what was the original price?

$45 \%$ of $1500 + 35 \%$ of $1700 = ? \%$ of $3175$

In an examination,$65 \%$ of students pass in History and $55 \%$ of students pass in Hindi. If $5 \%$ of students fail in both subjects,what is the percentage of students who passed in both subjects?

If the numerator of a fraction is increased by $150 \%$ and the denominator of the fraction is increased by $300 \%$,the resultant fraction is $\frac{5}{18}$. What is the original fraction?

Three candidates contested an election and received $1136$,$7636$,and $11628$ votes respectively. What percentage of the total votes did the winning candidate get?

Vedclass Test Series

Exam Paper Generator

Online Exam Module