A ladder 10, m long reaches a window 8, m abo | vedclass

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Question

(A) Let $OA$ be the wall and $AB$ be the ladder,where $OA = 8\, m$ and $AB = 10\, m$.Since the wall is perpendicular to the ground,$	riangle AOB$ is

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) Let $OA$ be the wall and $AB$ be the ladder,where $OA = 8\, m$ and $AB = 10\, m$.Since the wall is perpendicular to the ground,$	riangle AOB$ is a right-angled triangle with $\angle AOB = 90^\circ$.By Pythagoras theorem,$AB^2 = OA^2 + OB^2$.Substituting the values: $(10)^2 = (8)^2 + OB^2$.$100 = 64 + OB^2$.$OB^2 = 100 - 64 = 36$.$OB = \sqrt{36} = 6\, m$.Therefore,the distance of the foot of the ladder from the base of the wall is $6\, m$.

$A$ ladder $10\, m$ long reaches a window $8\, m$ above the ground. Find the distance of the foot of the ladder from the base of the wall. (in $, m$)

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