A lens of power +2 diopters is placed in cont | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power of a combination of thin lenses in contact is given by the algebraic sum of their individual powers: $P_{net} = P_1 + P_2$.Given $P_1 =

Vedclass · Accepted Answer

a convergent lens of focal length $100 \, cm$

Vedclass · Answer

(C) The power of a combination of thin lenses in contact is given by the algebraic sum of their individual powers: $P_{net} = P_1 + P_2$.Given $P_1 = +2 \, D$ and $P_2 = -1 \, D$.$P_{net} = (+2) + (-1) = +1 \, D$.Since the net power is positive,the combination behaves as a convergent (convex) lens.The focal length $f$ is given by $f = \frac{1}{P_{net}}$ (in meters).$f = \frac{1}{1} = 1 \, m = 100 \, cm$.Therefore,the combination behaves like a convergent lens of focal length $100 \, cm$.

$A$ lens of power $+2$ diopters is placed in contact with a lens of power $-1$ diopter. The combination will behave like

Similar Questions

$A$ lens of power $3.5 \, D$ is placed in contact with a lens of power $-2.5 \, D$. The combination behaves as:

The dispersive powers of the materials of two lenses forming an achromatic combination are in the ratio of $4:3$. If the effective focal length of the combination is $+60 \ cm$, then the focal lengths of the lenses should be:

Two plano-convex lenses,each of focal length $10 \, cm$ and refractive index $3/2$,are placed as shown in the figure. The space between them is filled with water $\left( \mu = 4/3 \right)$. The whole arrangement is in air. The optical power of the system is ....... $D$.

Obtain the equivalent focal length of a combination of thin lenses placed in contact.

Two thin lenses have a combined power of $+9 D$. When they are separated by a distance of $20 \,cm$, their equivalent power becomes $+\frac{27}{5} D$. Their individual powers (in diopters) are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module