A lift is moving downwards with an accelerati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The normal force $N$ acting on the body of mass $m$ inside the lift can be calculated using Newton's second law.For a lift moving downwards with a

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(D) The normal force $N$ acting on the body of mass $m$ inside the lift can be calculated using Newton's second law.For a lift moving downwards with acceleration $a$,the equation of motion is $mg - N = ma$.Given that the lift is moving downwards with an acceleration equal to the acceleration due to gravity,we have $a = g$.Substituting $a = g$ into the equation: $mg - N = mg$.This simplifies to $N = mg - mg = 0$.The frictional force $f$ is given by $f = \mu N$.Since the normal force $N = 0$,the frictional resistance $f = \mu 	imes 0 = 0$.Therefore,the correct option is $D$.

$A$ lift is moving downwards with an acceleration equal to the acceleration due to gravity. $A$ body of mass $m$ kept on the floor of the lift is pulled horizontally. If the coefficient of friction is $\mu$,then the frictional resistance offered by the body is:

Similar Questions

Find the apparent weight of a body of mass $1.0 \,kg$ falling with an acceleration of $10 \,ms^{-2}$. $\left(g \approx 10 \,ms^{-2}\right)$

$A$ man of weight $mg$ is in a lift moving up with an acceleration of $4g$. The apparent weight of the man in the lift is:

The minimum acceleration that must be imparted to the cart in the figure so that the block $A$ will not fall (given $\mu$ is the coefficient of friction between the surfaces of the block and the cart) is given by

$A$ man is standing on a weighing machine placed in a lift. When stationary,his weight is recorded as $40 \, kg$. If the lift is accelerated upwards with an acceleration of $2 \, m/s^2$,then the weight recorded in the machine will be .......... $kg$ $(g = 10 \, m/s^2)$.

$A$ plumb bob is hanging from the ceiling of a car. If the car moves with an acceleration $a$,the angle made by the string with the vertical is

Vedclass Test Series

Exam Paper Generator

Online Exam Module