A light and a heavy body have equal kinetic e | vedclass

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(A) The kinetic energy $(KE)$ of a body is given by the formula $KE = \frac{1}{2}mv^2$,where $m$ is the mass and $v$ is the velocity.Given that the ki

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The light body

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(A) The kinetic energy $(KE)$ of a body is given by the formula $KE = \frac{1}{2}mv^2$,where $m$ is the mass and $v$ is the velocity.Given that the kinetic energy of both bodies is equal,we have $\frac{1}{2}m_1v_1^2 = \frac{1}{2}m_2v_2^2$.This implies $m_1v_1^2 = m_2v_2^2$,or $\frac{v_1^2}{v_2^2} = \frac{m_2}{m_1}$.If $m_1  1$.Therefore,$\frac{v_1^2}{v_2^2} > 1$,which means $v_1^2 > v_2^2$,or $v_1 > v_2$.Thus,the lighter body must be moving faster to possess the same kinetic energy as the heavier body.

$A$ light and a heavy body have equal kinetic energy. Which one is moving fast?

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