A light string fixed at one end to a clamp on | vedclass

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Question

(C) Let $T$ be the tension in the string.The vertical component of the force exerted by the string on the clamp is given by $F_v = T \sin 30^{\circ}$.

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) Let $T$ be the tension in the string.The vertical component of the force exerted by the string on the clamp is given by $F_v = T \sin 30^{\circ}$.Given that the clamp can tolerate a maximum vertical force of $40 \, N$,we have:$T \sin 30^{\circ} = 40 \, N$$T 	imes (1/2) = 40 \, N$$T = 80 \, N$Now,consider the monkey climbing up the rope with an upward acceleration $a$. The forces acting on the monkey are the tension $T$ upwards and its weight $mg$ downwards.Using Newton's second law for the monkey:$T - mg = ma$$80 - (5 	imes 10) = 5a$$80 - 50 = 5a$$30 = 5a$$a = 6 \, m/s^2$Thus,the maximum acceleration with which the monkey can climb safely is $6 \, m/s^2$.

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