$A$ loop $ABCDEFA$ of straight edges has six corner points $A(0,0,0), B(5,0,0), C(5,5,0), D(0,5,0), E(0,5,5)$ and $F(0,0,5)$. The magnetic field in this region is $\overrightarrow{B}=(3 \hat{i}+4 \hat{k}) \; T$. The quantity of magnetic flux through the loop $ABCDEFA$ (in $\text{Wb}$) is:

Consider a closed loop $C$ in a magnetic field as shown in the figure. The flux passing through the loop is defined by choosing a surface whose edge coincides with the loop and using the formula $\phi = \sum \vec{B}_i \cdot d\vec{A}_i$. Now,if we choose two different surfaces $S_1$ and $S_2$ having $C$ as their edge,would we get the same answer for the magnetic flux? Justify your answer.

$A$ circular loop of radius $R$ carrying current $I$ lies in the $x-y$ plane with its centre at the origin. The total magnetic flux through the $x-y$ plane is:

Consider a circular coil of wire carrying constant current $I$,forming a magnetic dipole. The magnetic flux through an infinite plane that contains the circular coil and excluding the circular coil area is given by $\phi_{i}$. The magnetic flux through the area of the circular coil area is given by $\phi_{0}$. Which of the following options is correct?

$A$ square loop of side $2 \ m$ lies in the $Y-Z$ plane in a region having a magnetic field $\vec{B}=(5 \hat{i}+3 \hat{j}-4 \hat{k}) \ T$. The magnitude of magnetic flux through the square loop is (in $Wb$)

$A$ square coil of area $10^{-2} \ m^2$ is placed perpendicular to a uniform magnetic field of intensity $10^3 \ Wb/m^2$. The magnetic flux through the coil is ........ $Wb$.