A man sets his watch by the sound of a siren | vedclass

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Question

(B) The time taken by the sound to travel from the siren to the man is given by the formula: $t = \frac{d}{v}$.Given,distance $d = 1 \,km = 1000 \,m$

Vedclass · Accepted Answer

His watch is set $3 \,s$ slower

Vedclass · Answer

(B) The time taken by the sound to travel from the siren to the man is given by the formula: $t = \frac{d}{v}$.Given,distance $d = 1 \,km = 1000 \,m$ and velocity of sound $v = 330 \,m/s$.Calculating the time: $t = \frac{1000}{330} \approx 3.03 \,s$.Since the sound reaches the man $3.03 \,s$ after it is produced,the man hears the siren $3.03 \,s$ late.Therefore,when he sets his watch to the time he hears the sound,his watch will be $3.03 \,s$ behind the actual time.Thus,his watch is set approximately $3 \,s$ slower.

$A$ man sets his watch by the sound of a siren placed at a distance of $1 \,km$ away. If the velocity of sound is $330 \,m/s$,what is the status of his watch?

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