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(B) First,convert the speed of the man from $km/h$ to $m/s$:Speed $= 3 	imes \frac{5}{18} = \frac{5}{6} \, m/s$.Next,calculate the distance covered i

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$5000$

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(B) First,convert the speed of the man from $km/h$ to $m/s$:Speed $= 3 	imes \frac{5}{18} = \frac{5}{6} \, m/s$.Next,calculate the distance covered in $2 \, minutes$ $(120 \, seconds)$:Distance $= 	ext{Speed} 	imes 	ext{Time} = \frac{5}{6} 	imes 120 = 100 \, m$.Since the man crosses the square field diagonally,the diagonal $d$ of the square is $100 \, m$.The formula for the diagonal of a square is $d = a\sqrt{2}$,where $a$ is the side length.$a\sqrt{2} = 100 \Rightarrow a = \frac{100}{\sqrt{2}}$.The area of the square is $a^2$:Area $= \left(\frac{100}{\sqrt{2}}ight)^2 = \frac{10000}{2} = 5000 \, m^2$.

$A$ man walking at $3 \, km/h$ crosses a square field diagonally in $2 \, minutes$. The area of the field (in $m^2$) is:

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