(D) Volume of the wall $= 270 \times 300 \times 350 = 28,350,000 \,cm^3$.Since $\frac{1}{8}$ of the wall's volume is occupied by mortar,the volume occ

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(D) Volume of the wall $= 270 \times 300 \times 350 = 28,350,000 \,cm^3$.Since $\frac{1}{8}$ of the wall's volume is occupied by mortar,the volume occupied by the bricks is $\frac{7}{8}$ of the total volume.Volume occupied by bricks $= 28,350,000 \times \frac{7}{8} = 24,806,250 \,cm^3$.Volume of one brick $= 22.5 \times 11.25 \times 8.75 = 2,214.84375 \,cm^3$.Number of bricks $= \frac{\text{Volume occupied by bricks}}{\text{Volume of one brick}} = \frac{24,806,250}{2,214.84375} = 11,200$.Therefore,the number of bricks used is $11,200$.

Class 10 Mathematics Surface Areas and Volumes Mix Examples - Surface Areas and Volumes

Difficult

$A$ mason constructs a wall of dimensions $270 \,cm \times 300 \,cm \times 350 \,cm$ with bricks each of size $22.5 \,cm \times 11.25 \,cm \times 8.75 \,cm$. If $\frac{1}{8}$ of the total volume of the wall is occupied by mortar,find the number of bricks used to construct the wall.

A
$11000$
B
$11100$
C
$11300$
D
$11200$

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Surface Areas and Volumes

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Mix Examples - Surface Areas and Volumes

$A$ factory manufactures $120000$ pencils daily. The pencils are cylindrical in shape,each of length $25 \,cm$ and circumference of base $1.5 \,cm$. Determine the cost of colouring the curved surfaces of the pencils manufactured in one day at $\operatorname{Rs.} 0.05$ per $dm^2$ (in $Rs.$).

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The base of a cone is hemispherical. The radius of the cone is $15 \, cm$ and the total height of the solid is $55 \, cm$. Find the volume of this solid (in $cm^3$).

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Write 'True' or 'False' and justify your answer:
Two identical solid hemispheres of equal base radius $r \text{ cm}$ are joined together along their bases. The total surface area of the resulting solid is $6 \pi r^{2}$.

Easy

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The diameters of a frustum of a cone are $32 \,cm$ and $20 \,cm$. If its height is $8 \,cm$,find its curved surface area and volume. $(\pi = 3.14)$

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The area of the base of a cylinder is $616\,cm^{2}$. Then,the radius of the base of the cylinder is $\ldots \ldots \ldots \ldots cm.$

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$A$ mason constructs a wall of dimensions $270 \,cm \times 300 \,cm \times 350 \,cm$ with bricks each of size $22.5 \,cm \times 11.25 \,cm \times 8.75 \,cm$. If $\frac{1}{8}$ of the total volume of the wall is occupied by mortar,find the number of bricks used to construct the wall.

Similar Questions

$A$ factory manufactures $120000$ pencils daily. The pencils are cylindrical in shape,each of length $25 \,cm$ and circumference of base $1.5 \,cm$. Determine the cost of colouring the curved surfaces of the pencils manufactured in one day at $\operatorname{Rs.} 0.05$ per $dm^2$ (in $Rs.$).

The base of a cone is hemispherical. The radius of the cone is $15 \, cm$ and the total height of the solid is $55 \, cm$. Find the volume of this solid (in $cm^3$).

Write 'True' or 'False' and justify your answer:Two identical solid hemispheres of equal base radius $r \text{ cm}$ are joined together along their bases. The total surface area of the resulting solid is $6 \pi r^{2}$.

The diameters of a frustum of a cone are $32 \,cm$ and $20 \,cm$. If its height is $8 \,cm$,find its curved surface area and volume. $(\pi = 3.14)$

The area of the base of a cylinder is $616\,cm^{2}$. Then,the radius of the base of the cylinder is $\ldots \ldots \ldots \ldots cm.$

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Write 'True' or 'False' and justify your answer:
Two identical solid hemispheres of equal base radius $r \text{ cm}$ are joined together along their bases. The total surface area of the resulting solid is $6 \pi r^{2}$.