A mass M is placed on a smooth wedge of angle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To keep the mass $M$ at rest relative to the wedge,we analyze the forces in the non-inertial frame of the wedge.When the wedge accelerates to the

Vedclass · Accepted Answer

$a$ is applied to the left and $a=g 	an 	heta$

Vedclass · Answer

(D) To keep the mass $M$ at rest relative to the wedge,we analyze the forces in the non-inertial frame of the wedge.When the wedge accelerates to the left with acceleration $a$,a pseudo force $F_p = Ma$ acts on the mass $M$ towards the right.The forces acting on the mass $M$ along the incline are:$1$. The component of pseudo force $Ma \cos 	heta$ acting up the incline.$2$. The component of gravitational force $Mg \sin 	heta$ acting down the incline.For the mass to remain at rest relative to the wedge,these two forces must balance:$Ma \cos 	heta = Mg \sin 	heta$$a \cos 	heta = g \sin 	heta$$a = g \frac{\sin 	heta}{\cos 	heta}$$a = g 	an 	heta$Thus,an acceleration $a = g 	an 	heta$ must be applied to the wedge towards the left.

$A$ mass $M$ is placed on a smooth wedge of angle $\theta$ resting on a frictionless surface. To keep the mass $M$ at rest relative to the wedge,the wedge must be given a horizontal acceleration $a$ equal to:

Similar Questions

Three weights $W, 2W$,and $3W$ are connected to identical springs suspended from a rigid horizontal rod. The assembly of the rod and the weights falls freely under gravity. The positions of the weights from the rod are such that:

$A$ man weighing $60 \text{ kg}$ is in a lift moving down with an acceleration of $1.8 \text{ ms}^{-2}$. The force exerted by the floor on him is:

$A$ boy whose mass is $50\,kg$ stands on a spring balance inside a lift. The lift starts to ascend with an acceleration of $2\,m/s^2$. The reading of the machine or balance $(g = 10\,m/s^2)$ is ........ $kg$.

The weight of a man in a lift moving with the same acceleration upwards is $608 \ N$,while the weight of the same man in the lift moving downwards with the same acceleration is $368 \ N$. His normal weight is ............ $N$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module