$A$ mass of $20\ kg$ is hanging with the support of two strings of the same linear mass density. Now,pulses are generated in both strings at the same time near the joint at the mass. The ratio of the time taken by a pulse to travel through string $1$ to that taken by a pulse on string $2$ is:

If the tension in a wire is made four times,then what will be the change in the speed of the wave propagating in it?

$A$ string of mass $0.2 \ kg$ is under a tension of $2.5 \ N$. The length of the string is $2 \ m$. $A$ transverse wave starts from one end of the string. The time taken by the wave to reach the other end is: (in $s$)

$A$ wire of linear mass density $\mu = 10^{-2} \, kg \, m^{-1}$ passes over a frictionless light pulley fixed on the top of a frictionless inclined plane which makes an angle of $30^o$ with the horizontal. Masses $m$ and $M$ are tied at two ends of the wire such that $m$ rests on the plane and $M$ hangs freely vertically downwards. The entire system is in equilibrium and a transverse wave propagates along the wire with a velocity of $100 \, m \, s^{-1}$.

$A$ transverse pulse generated at the bottom of a uniform rope of length $L$ travels in an upward direction. The time taken by it to travel the full length of the rope will be

Two strings $(A, B)$ having linear densities $\mu_{A} = 2 \times 10^{-4} \ kg/m$ and $\mu_{B} = 4 \times 10^{-4} \ kg/m$ and lengths $L_{A} = 2.5 \ m$ and $L_{B} = 1.5 \ m$ respectively are joined. Free ends of $A$ and $B$ are tied to two rigid supports $C$ and $D$, respectively, creating a tension of $500 \ N$ in the wire. Two identical pulses, sent from $C$ and $D$ ends, take time $t_1$ and $t_2$, respectively, to reach the joint. The ratio $t_1 / t_2$ is: