A mixture contains alcohol and water in the r | vedclass

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Question

(C) Let the initial quantity of alcohol be $4x$ and water be $3x$.When $5 	ext{ liters}$ of water is added,the new quantity of water becomes $3x + 5$

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) Let the initial quantity of alcohol be $4x$ and water be $3x$.When $5 	ext{ liters}$ of water is added,the new quantity of water becomes $3x + 5$.According to the problem,the new ratio of alcohol to water is $4:5$.So,$\frac{4x}{3x + 5} = \frac{4}{5}$.Cross-multiplying,we get $20x = 4(3x + 5)$.$20x = 12x + 20$.$8x = 20$.$x = \frac{20}{8} = 2.5$.The quantity of alcohol is $4x = 4 	imes 2.5 = 10 	ext{ liters}$.

$A$ mixture contains alcohol and water in the ratio $4:3$. If $5 \text{ liters}$ of water is added to the mixture,the ratio becomes $4:5$. Find the quantity of alcohol in the given mixture (in $\text{L}$).

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