A motorcycle is moving on an overbridge of ra | vedclass

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(A) For a vehicle moving on a convex bridge of radius $R$ at a speed $v$,the forces acting on it are the gravitational force $mg$ acting downwards and

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Increases

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(A) For a vehicle moving on a convex bridge of radius $R$ at a speed $v$,the forces acting on it are the gravitational force $mg$ acting downwards and the normal force $N$ acting upwards. The component of the gravitational force perpendicular to the bridge surface is $mg \cos 	heta$,where $	heta$ is the angle with the vertical.Applying Newton's second law for circular motion in the radial direction:$mg \cos 	heta - N = \frac{mv^2}{R}$Therefore,the normal force is given by:$N = mg \cos 	heta - \frac{mv^2}{R}$As the motorcycle ascends the overbridge,the angle $	heta$ (the angle with the vertical) decreases from $90^{\circ}$ to $0^{\circ}$.As $	heta$ decreases,$\cos 	heta$ increases.Since $N = mg \cos 	heta - \frac{mv^2}{R}$,as $\cos 	heta$ increases,the normal force $N$ increases.

$A$ motorcycle is moving on an overbridge of radius $R$. The driver maintains a constant speed $v$. As the motorcycle is ascending on the overbridge,the normal force on it

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