A non-conducting ring of radius 0.5,m carries | vedclass

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(A) The line integral of the electric field from infinity to a point $P$ is defined as the electric potential $V$ at that point.$\int_{\infty}^{P} -\v

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$2$

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(A) The line integral of the electric field from infinity to a point $P$ is defined as the electric potential $V$ at that point.$\int_{\infty}^{P} -\vec{E} \cdot d\vec{l} = V_P - V_{\infty}$.Since the potential at infinity $V_{\infty} = 0$,the integral represents the potential at the centre of the ring.For a ring of radius $R$ with total charge $q$,the potential at the centre is given by $V = \frac{1}{4\pi\epsilon_0} \frac{q}{R}$.Given $q = 1.11 	imes 10^{-10}\,C$,$R = 0.5\,m$,and $\frac{1}{4\pi\epsilon_0} = 9 	imes 10^9\,N\cdot m^2/C^2$.$V = (9 	imes 10^9) 	imes \frac{1.11 	imes 10^{-10}}{0.5} = \frac{9.99 	imes 10^{-1}}{0.5} = \frac{0.999}{0.5} \approx 2\,V$.

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