$A$ normal to the hyperbola $4x^2 - 9y^2 = 36$ meets the coordinate axes $x$ and $y$ at $A$ and $B$,respectively. If the parallelogram $OABP$ ($O$ being the origin) is formed,then the locus of $P$ is

  • A
    $4x^2 - 9y^2 = 121$
  • B
    $4x^2 + 9y^2 = 121$
  • C
    $9x^2 - 4y^2 = 169$
  • D
    $9x^2 + 4y^2 = 169$

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