A normal woman whose father was colour blind, | vedclass

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Question

(B) Colour blindness is an $X$-linked recessive trait.$1$. The woman is normal but her father was colour blind,so she must be a carrier for the trait.

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$50\%$ colour blind

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(B) Colour blindness is an $X$-linked recessive trait.$1$. The woman is normal but her father was colour blind,so she must be a carrier for the trait. Her genotype is $X^hX$.$2$. The man is normal,so his genotype is $XY$.$3$. The cross between the carrier woman $(X^hX)$ and the normal man $(XY)$ results in the following offspring:- $X^hX$ (Carrier daughter)- $XX$ (Normal daughter)- $X^hY$ (Colour blind son)- $XY$ (Normal son)$4$. Among the sons,one is colour blind $(X^hY)$ and one is normal $(XY)$. Therefore,$50\%$ of the sons would be colour blind.

$A$ normal woman whose father was colour blind,is married to a normal man. The sons would be

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