A woman has a haemophilic son and three norma | vedclass

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(D) Haemophilia is an $X$-linked recessive disorder.Since the woman has a haemophilic son $(X^hY)$,the son must have inherited the $X^h$ chromosome fr

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$X^hX$ and $XY$

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(D) Haemophilia is an $X$-linked recessive disorder.Since the woman has a haemophilic son $(X^hY)$,the son must have inherited the $X^h$ chromosome from his mother.Therefore,the mother must be a carrier of the haemophilia gene,meaning her genotype is $X^hX$.Since the woman also has normal children and the husband is not mentioned as haemophilic,we assume the husband is normal $(XY)$.Thus,the genotype of the woman is $X^hX$ and the husband is $XY$.

$A$ woman has a haemophilic son and three normal children. Her genotype and that of her husband with respect to this gene would be

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