A nucleus of mass number 189 splits into two | vedclass

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(B) The radius $R$ of a nucleus with mass number $A$ is given by the formula: $R = R_{0} A^{1/3}$, where $R_{0}$ is a constant.For the two daughter nu

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$5: 4$

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(B) The radius $R$ of a nucleus with mass number $A$ is given by the formula: $R = R_{0} A^{1/3}$, where $R_{0}$ is a constant.For the two daughter nuclei with mass numbers $A_{1} = 125$ and $A_{2} = 64$, their radii $R_{1}$ and $R_{2}$ are:$R_{1} = R_{0} (125)^{1/3} = R_{0} 	imes 5$$R_{2} = R_{0} (64)^{1/3} = R_{0} 	imes 4$The ratio of the radii is:$\frac{R_{1}}{R_{2}} = \frac{R_{0} (125)^{1/3}}{R_{0} (64)^{1/3}} = \frac{5}{4}$Thus, the ratio is $5: 4$.

$A$ nucleus of mass number $189$ splits into two nuclei having mass numbers $125$ and $64$. The ratio of the radii of the two daughter nuclei is:

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