$A$ parallel plate capacitor is charged to $60\,\mu C$. Due to a radioactive source,the plate loses charge at the rate of $1.8 \times 10^{-8}\, C/s$. The magnitude of the displacement current is:

If the rate of change in electric flux between the plates of a capacitor is $9 \pi \times 10^3 \text{ Vm s}^{-1}$,then the displacement current inside the capacitor is (in $\mu \text{A}$)

The charge on a capacitor varies with time as $q = q_0 \sin(2\pi nt)$. What is the displacement current produced in the dielectric of the capacitor?

The figure shows a capacitor made of two circular plates,each of radius $12 \; cm$,separated by $5.0 \; cm$. The capacitor is being charged by an external source (not shown in the figure). The charging current is constant and equal to $0.15 \; A$.
$(a)$ Calculate the capacitance and the rate of change of potential difference between the plates.
$(b)$ Obtain the displacement current across the plates.
$(c)$ Is Kirchhoff's first rule (junction rule) valid at each plate of the capacitor? Explain.

When a displacement current $i_d$ flows in the region between the two plates of a capacitor,the charge on the capacitor is:

Match List-$I$ with List-$II$.

List-$I$ (Relation)	List-$II$ (Law)
$A$. $\oint \overrightarrow{E} \cdot d\vec{l} = -\frac{d}{dt} \oint \overrightarrow{B} \cdot d\vec{a}$	$I$. Ampere's circuital law
$B$. $\oint \vec{B} \cdot d\vec{l} = \mu_0(I + \epsilon_0 \frac{d\phi_E}{dt})$	$II$. Faraday's laws of electromagnetic induction
$C$. $\oint \overrightarrow{E} \cdot d\vec{a} = \frac{1}{\epsilon_0} \int \rho dv$	$III$. Ampere-Maxwell law
$D$. $\oint \overrightarrow{B} \cdot d\vec{l} = \mu_0 I$	$IV$. Gauss's law of electrostatics

Choose the correct answer from the options given below: