$A$ particle $A$ has charge $+q$ and a particle $B$ has charge $+4q$,with each of them having the same mass $m$. When allowed to fall from rest through the same electric potential difference,the ratio of their speeds $\frac{v_A}{v_B}$ will be:

  • A
    $2:1$
  • B
    $1:2$
  • C
    $1:4$
  • D
    $4:1$

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