A particle initially at rest is subjected to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the constant force be $F$ and the retarding force be $-kv$,where $k$ is a positive constant and $v$ is the velocity.The net force on the parti

Vedclass · Accepted Answer

Both $(B)$ and $(C)$

Vedclass · Answer

(D) Let the constant force be $F$ and the retarding force be $-kv$,where $k$ is a positive constant and $v$ is the velocity.The net force on the particle is $F_{net} = F - kv$.According to Newton's second law,$ma = F - kv$,where $a = dv/dt$.Initially,at $t = 0$,$v = 0$,so the initial acceleration is $a_0 = F/m$.As the particle moves,$v$ increases,which causes the retarding force $kv$ to increase.Consequently,the net force $F - kv$ decreases,meaning the acceleration $a = (F - kv)/m$ decreases from its initial value $F/m$ towards zero.As $t 	o \infty$,the acceleration approaches zero,and the velocity approaches a constant terminal value $v_t = F/k$ where the net force becomes zero.Thus,both statements $(B)$ and $(C)$ are correct.

$A$ particle initially at rest is subjected to two forces. One is constant,the other is a retarding force proportional to the particle velocity. In the subsequent motion of the particle,

Similar Questions

$A$ truck starting from rest moves with an acceleration of $5 \, m/s^2$ for $1 \, s$ and then moves with constant velocity. The velocity $w.r.t$ ground $v/s$ time graph for the block in the truck is (Assume that the block does not fall off the truck and the coefficient of friction $\mu = 0.2$):

$A$ spring-block system is placed on a rough horizontal floor. The block is pulled towards the right to give the spring some elongation and then released.

$A$ particle of mass $7 \, kg$ moving at $5 \, m/s$ is acted upon by a variable force opposite to its initial direction of motion. The variation of force $F$ with time $t$ is shown in the graph.

$A$ block of mass $m$ moves on a horizontal rough surface with initial velocity $v$. The height of the centre of mass of the block is $h$ from the surface. Consider a point $A$ on the surface.

Vedclass Test Series

Exam Paper Generator

Online Exam Module