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(B) The displacement of the particle is given by $x = A \cos (\omega t - 	heta)$.To find the velocity $v$,we differentiate the displacement with resp

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$A \omega$

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(B) The displacement of the particle is given by $x = A \cos (\omega t - 	heta)$.To find the velocity $v$,we differentiate the displacement with respect to time $t$:$v = \frac{dx}{dt} = \frac{d}{dt} [A \cos (\omega t - 	heta)]$$v = -A \omega \sin (\omega t - 	heta)$The velocity is maximum when the magnitude of the sine function is $1$,i.e.,$|\sin (\omega t - 	heta)| = 1$.Therefore,the maximum velocity is $v_{\max} = | -A \omega (1) | = A \omega$.Thus,the maximum velocity of the particle is $A \omega$.

$A$ particle is executing the motion $x = A \cos (\omega t - \theta)$. The maximum velocity of the particle is

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