$A$ particle is moving along a circle such that it completes one revolution in $40 \, s$. In $2 \, \text{minutes} \, 20 \, s$, the ratio $\frac{|\text{displacement}|}{\text{distance}}$ is:

The angular velocity of the seconds hand of a watch will be:

$A$ particle is moving in a horizontal circle with constant speed. It has constant

$A$ particle is acted upon by a force of constant magnitude such that its velocity and acceleration are always perpendicular to each other, then its

If $\vec{L}$ and $\vec{P}$ represent the angular momentum and linear momentum respectively of a particle of mass $m$ having position vector $\vec{r} = a(\hat{i} \cos \omega t + \hat{j} \sin \omega t)$,the direction of the force acting on the particle is:

$A$ particle moves with a constant speed $v$ along a circle of radius $R$. What is the change in velocity of the particle as it moves from point $P_1$ to $P_2$?