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Question

(B) The angular momentum $L_O$ of a particle about a point $O$ is defined as the cross product of its position vector $\vec{r}$ and its linear momentu

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$mvl$

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(B) The angular momentum $L_O$ of a particle about a point $O$ is defined as the cross product of its position vector $\vec{r}$ and its linear momentum $\vec{p} = m\vec{v}$.Mathematically,$L_O = |\vec{r} 	imes \vec{p}| = m v d_{\perp}$,where $d_{\perp}$ is the perpendicular distance (lever arm) from the point $O$ to the line of motion of the particle.From the given figure,the perpendicular distance from point $O$ to the line $PC$ is $l$.Therefore,the angular momentum of the particle about $O$ is $L_O = mvl$.

$A$ particle of mass $m$ moves along line $PC$ with velocity $v$ as shown. What is the angular momentum of the particle about $O$?

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