$A$ particle of small mass $m$ is joined to a very heavy body of mass $M$ by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is

Two masses of $1\, kg$ and $5\, kg$ are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in the figure. When the masses are released and start moving,the reading of the spring balance will be:

$A$ rope of length $5\,m$ is kept on a frictionless surface and a force of $5\,N$ is applied to one of its ends. Find the tension in the rope at $1\,m$ from this end.

$A$ block of mass $1\,kg$ is suspended by a string of mass $1\,kg$ and length $1\,m$ as shown in the figure. Given $g = 10\,m/s^2$,calculate the tension in the string at its mid-point. (in $,N$)

Consider a body of mass $3\,kg$ at rest on a smooth horizontal table. This body is connected by a light string,which passes over a smooth pulley at the edge of the table,to another body of mass $2\,kg$ hanging freely. This $2\,kg$ mass is released from rest. Now consider the following statements:
$(A)$ The masses remain at rest.
$(B)$ The $3\,kg$ mass moves uniformly while the $2\,kg$ mass moves with acceleration $\frac{2}{5}g\,m/s^2$.
$(C)$ Both bodies move with acceleration $\frac{2}{5}g\,m/s^2$.
$(D)$ The tension in the string near the first body is more than that near the second body.
$(E)$ The tension in the string is $\frac{6g}{5}\,N$.
Then the correct statements are:

$A$ man is pulling on a rope attached to a block on a smooth horizontal table. The tension in the rope will be the same at all points: