A pendulum clock is placed inside an elevator | vedclass

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(C) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due to gravity.

Vedclass · Accepted Answer

Shows correct time when descending with constant speed.

Vedclass · Answer

(C) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due to gravity.When an elevator moves with constant velocity (constant speed in a straight line),its acceleration is zero.In this case,the effective acceleration $g_{eff} = g$,which is the same as when the elevator is at rest.Therefore,the time period $T$ remains unchanged,and the clock shows the correct time.If the elevator accelerates,$g_{eff}$ changes $(g_{eff} = g \pm a)$,causing the clock to gain or lose time.

$A$ pendulum clock is placed inside an elevator. Under what condition does it show the correct time?

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